# Question 1a9d7

Jul 16, 2016

A

#### Explanation:

N° of Protons for 1 mol of salt= 50 (Ca= 30; C= 6; O = 8 x 3 = 24)
N° mol = Mg/ MM = 10g/(100 g/mol) = 0,1
N° of protons in 1 mol of protons = Na = 6,022 X 10^23
50 x 0,1 x 6,022 x 10^23 = 3,011 x 10 ^23

Jul 16, 2016

The correct answer is "None of the above".

#### Explanation:

Step 1. Calculate the number of protons in one formula unit of ${\text{CaCO}}_{3}$.

$\text{Number of protons" = "Ca + C + 3O" = "20 + 6 + 3×} 8 = 50$

2. Calculate the moles of ${\text{CaCO}}_{3}$

${\text{Moles of CaCO"_3 = 10 color(red)(cancel(color(black)("g CaCO"_3))) × ("1 mol CaCO"_3)/(100.09 color(red)(cancel(color(black)("g CaCO"_3)))) = "0.0999 mol CaCO}}_{3}$

3. Calculate the number of formula units of ${\text{CaCO}}_{3}$

${\text{Formula units" = 0.0999 color(red)(cancel(color(black)("mol CaCO"_3))) × (6.022 × 10^23color(white)(l) "formula units CaCO"_3)/(1 color(red)(cancel(color(black)("mol CaCO"_3)))) = 6.02 × 10^22color(white)(l) "formula units CaCO}}_{3}$

4. Calculate the total number of protons

"Number of protons" = 6.02 × 10^22 color(red)(cancel(color(black)("formula units"))) × "50 protons"/(1 color(red)(cancel(color(black)("formula unit"))))

= 3.0 × 10^24color(white)(l) "protons"#

This answer is not in the above list.

∴ The correct answer is "None of the above".