# Question #313e5

##### 2 Answers

#### Answer:

The reqd. larger even

#### Explanation:

Let the reqd. **first even integer** be **next to this even integer** will be **not**

Now, "The square of the sum of 2 consecutive positive even integers"

Next, "the sum of their squares"

We are given that,

Hence, we have,

Dividing throughout by

since we need

Hence, the reqd. larger even

Hope, this'll help! Enjoy Maths.!

#### Answer:

The other solutions are correct. This is a very slightly different approach. Upon reflection, it is virtually the same as that by Ratnaker

The larger number is 10

#### Explanation:

The two numbers are even so my starting point is to make sure the first integer is even (divisible by 2)

Let the 'seed value' (can be even or odd) be

Then

Let the first number be

Let the second number be

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The square of the sum of 2 consec. numb.

is greater than

the sum of their squares

by 160

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Divide by 8

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~