If the gravity of the moon is about #1/6#th the gravity on earth, how will a clock's period on the moon compare with that on earth?

1 Answer
Aug 13, 2016


Will run slow


For small-ish oscillations, we know that period, T, of an oscillation is #T = 2 pi sqrt (l/g)# where l is the length of the pendulum and g is prevailing gravity

as #g_(mo on) approx (g_(earth))/6#

then #T_(mo on) approx sqrt6 * T_(earth)=2.45*T_(earth)#

So, if you like, a tick and a tock should take 2.45 times as long and the clock should run slow.