# If the gravity of the moon is about 1/6th the gravity on earth, how will a clock's period on the moon compare with that on earth?

Aug 13, 2016

Will run slow

#### Explanation:

For small-ish oscillations, we know that period, T, of an oscillation is $T = 2 \pi \sqrt{\frac{l}{g}}$ where l is the length of the pendulum and g is prevailing gravity

as ${g}_{m o o n} \approx \frac{{g}_{e a r t h}}{6}$

then ${T}_{m o o n} \approx \sqrt{6} \cdot {T}_{e a r t h} = 2.45 \cdot {T}_{e a r t h}$

So, if you like, a tick and a tock should take 2.45 times as long and the clock should run slow.