Question #e58ac

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Question #e58ac

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Answer 1 · 2016-08-13T14:58:17

$F_{2} = \frac{F_{1}}{4}$ $F_2=F_1/4$

Explanation:

$F_{1} = k \cdot \frac{q_{1} \cdot q_{2}}{d^{2}}$ $F_1=k*(q_1*q_2)/d^2$

$F_{2} = k \frac{q_{1} \cdot q_{2}}{{(2 d)}^{2}}$ $F_2=k(q_1*q_2)/(2d)^2$

$\frac{F_{1}}{F_{2}} = \frac{k \cdot \frac{q_{1} \cdot q_{2}}{d^{2}}}{k \cdot \frac{q_{1} \cdot q_{2}}{4 d^{2}}}$ $F_1/F_2=(k*(q_1*q_2)/d^2)/(k*(q_1*q_2)/(4d^2))$

$F_1/F_2=cancel(k)*(cancel(q_1*q_2))/cancel(d^2)*(4*cancel(d^2))/(cancel(k)*cancel(q_1*q_2))$

$F_1/F_2=4$

$F_2=F_1/4$

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Question #e58ac

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