# Question #a87b0

Starting with say 1.0 mole/Liter NaOH in aqueous solution and titrating to end point with strong acid ( ~HCl(aq)) gives concentration of the Hydroxide ion $\left(O {H}^{-}\right)$ in solution to equal 1.0 moles/Liter. Such is the starting amount of NaOH measured and dissolved into solution.
That is, for $N a O H \left(a q\right) \implies N {a}^{+} \left(a q\right) + O {H}^{-} \left(a q\right)$
$\left[O {H}^{-}\right] = \left[N a O H\right]$ at end point & indicates 100% dissociation.