# Question #0db4c

Oct 14, 2017

$\textcolor{red}{A = 35}$

#### Explanation:

${2}^{2} - 1 - 9 \cdot {2}^{2} - 2 + 1 A = 0$

Rearranging the equation by combining the like terms :
$\left({2}^{2} - 9 \cdot {2}^{2}\right) - 1 - 2 + 1 A = 0$
${2}^{2} \left(1 - 9\right) - \left(1 + 2\right) + 1 A = 0$

$4 \cdot \left(- 8\right) - 3 + 1 A = 0 \textcolor{w h i t e}{a a a}$writing ${2}^{2} a s \textcolor{w h i t e}{a} 4$
$- 32 - 3 + A = 0$ as $\ast 1 A = A \ast$

$A = 32 + 3 = 35 \textcolor{w h i t e}{a a a}$ taking constant terms to R H S.