Question #dfffa

1 Answer
Jan 19, 2018

Answer:

The temperature coefficient of resistance is #5.7#x#10^(-3)##/##.^@"C"#.

Explanation:

The coefficient of resistance is given by the equation below:

#rArr##R(T)=R_o[1+alpha(T-T_o)]#
where #R# is the resistance at temperature #T# and #R_o# is the resistance at temperature #T_o#. Also #'alpha'# is the coefficient of resistivity.

From above equation we can write
#rArr##alpha = [(R/R_o)-1]xx[1/(T-T_o)]#
Considering the values as #R=5Omega,T=50^@"C"# and #R_o=7Omega,T_o=100^@"C"#, and substituting them we get,
#rArr##alpha = [(5Omega)/(7Omega)-1]xx[1/(50^@"C"-100^@"C")]#
#=(0.71428571-1)xx(1/(-50^@"C"))#
#=(-0.2857143)xx(1/(-50^@"C"))=0.005714286/(1^@"C")#
Therefore the coefficient of resistance is #~~(5.7xx10^(-3))//.^@"C"#.