Current and Resistance
Add yours
Key Questions

Answer:
flow of charge
Explanation:
Materials in general can be as classified as conductors, semi conductors or insulators depending on the behaviour of charge carriars when a potential difference is applied across it.
In metals for example, the charge carriars are the electrons. Experiments reveal that electrons move randomly in a conductor, but when a PD is applied across it the electrons gain energy and move in a particular direction.
The movement of these charge carriars constitute electric current; 
Answer:
Electrical resistance is the repulsion of a current within a circuit.
Explanation:
It explains the relationship between voltage (amount of electrical pressure) and the current (flow of electricity). With more resistance in a circuit, less electricity will flow through the circuit.
Electrical resistance shares some conceptual parallels with the notion of mechanical friction. The SI unit of electrical resistance is the ohm (Î©), while electrical conductance is measured in siemens (S). 
Answer:
#V=I*R# Explanation:
Ohm's Law states that the electric potential (Voltage) is equal to the electric current times the resistance.
#V=I*R# Another way to think of this is how to increase the current (or flow).
To increase the current, we need to increase the voltage and/or decrease the resistance.
Example, find the current in a simple circuit that has a
#12"V"# battery and a wire with a resistance of#1.2 Omega# #I=V/R#
#I=(12"V")/(1.2Omega) = 10"A"# One way to remember the relationship between
#V# ,#I# and#R# is the#VIR# triangle:This can be read as
#V = I * R# or#I = V/R# or#V/I = R# 
A thicker wire (of the same material) has lower resistance.
Having a thicker wire means that the volume of conducting material has increased so there are more conduction electrons available.
A concrete example of this point would be consider the current that flows through a wire. Now take a second identical wire and set it parallel with the first. The current that flows through the parallel combination would be larger (by a factor of two). Therefore the resistance of that arrangement must be less than the single wire (half the resistance of the single wire).