# Question #eedef

Aug 27, 2016

It is assumed that the given reaction is a gaseous one as it deals with ${K}_{p}$ and the reversible reaction is represented by the following equation

${H}_{2} \left(g\right) + {I}_{2} \left(g\right) r i g h t \le f t h a r p \infty n s 2 H I$

We know that the relation between ${K}_{p} \mathmr{and} {K}_{c}$ of agaseous reaction is

${K}_{p} = {K}_{c} {\left(R T\right)}^{\Delta n} \ldots . \left(1\right)$

Where $T \to \text{Temperayure of the reaction in Kelvin}$

$R \to \text{Universal gas constant}$

$\Delta n \to \text{Total no. of moles of gaseous product"- "Total no. of moles of gaseous reactants}$

For the given reaction

$\Delta n = {n}_{H I \left(g\right)} - {n}_{{H}_{2} \left(g\right)} - {n}_{{I}_{2} \left(g\right)} = 2 - 1 - 1 = 0$

So by equation(1)

${K}_{p} = {K}_{c} {\left(R T\right)}^{\Delta n} = {K}_{c} {\left(R T\right)}^{0} = {K}_{c} = 50$