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Answer 1 · 2016-08-31T15:32:19

#g(a+ 3) = a^2 + 4a + 7#

When you were younger, the textbook would probably ask you such questions as:

If #f(x) = 2x + 1#, evaluate #f(3)#. You would just substitute #3# for x:

#f(3) = 2(3) + 1 = 7#

This problem is much the same; you just substitute #a + 3# for x.

#g(a + 3) = (a + 3)^2 - 2(a + 3) + 4#

#g(a + 3) = a^2 + 6a + 9 - 2a - 6 + 4#

#g(a + 3) = a^2 + 4a + 7#

Hopefully this helps!