# Question #706f8

##### 1 Answer

#### Answer:

It accelerates well.

#### Explanation:

In simple terms, **acceleration**, **velocity** of an object changes with respect to time.

#color(purple)(bar(ul(|color(white)(a/a)color(black)(a = (Deltav)/(Deltat)color(white)(a/a)|)))#

Here

**change** in the velocity of the object

**time** needed for this change to take place

The problem tells you that a car goes from **change** in the velocity of the car,

#Deltav = "60 mi/h" - "0 mi/h" = "60 mi/h"#

You also know that it takes **seconds** for this change in velocity to take place. If you take

#Deltat = "6 s" - "0 s" = "6 s"#

Since you know the values of **acceleration**.

To calculate it, you must *convert* the change in velocity to *meters per second* by using a series of *conversion factors*

#60 color(red)(cancel(color(black)("mi")))/(1color(red)(cancel(color(black)("h")))) * (1.61 color(red)(cancel(color(black)("km"))))/(1color(red)(cancel(color(black)("mi")))) * (10^3"m")/(1color(red)(cancel(color(black)("km")))) * (1color(red)(cancel(color(black)("h"))))/(60color(red)(cancel(color(black)("min")))) * (1color(red)(cancel(color(black)("min"))))/"60 s" = "26.83 m s"^(-1)#

You will have

#a = ("26.83 m s"^(-1))/"6 s" ~~ "4.5 m s"^(-2)#

What this tells you is that with **every passing second**, the velocity of the car **increases** by approximately

Therefore, because you know the change in velocity and the time needed for that change to take place, you can say that the car **accelerates** well.

It can be argued that you can *also* say that the car is fast, but for that to make a valid statement you'd need to know its **top speed**. In relative terms, a car that accelerates that well will most likely be very fast, but I don't think that this is the conclusion you must draw here.