What is #rho_"titanium"# in #lb*"inch"^-3#?

1 Answer
anor277
Sep 8, 2016

You want the density of titanium of metal in #lb*"inch"^-3#?

Explanation:

#rho_"titanium metal"# #=# #4.51*g*cm^-3#

There are #454*g*lb^-1#, and #2.54*cm*"inch"^-1#.

#rho_"titanium metal"# #=# #"Mass"/"Volume"#

#=# #4.51*cancelgxx1/(454*cancelg*lb^-1)xx1/(cancel(cm^3)xx(2.54*cancel(cm)*"inch"^-1)^3)#

#=# #0.163*lb*"inch"^-3#??

I think I've got this right; obviously you won't build a titanium structure on my say so! I would be more sanguine about my answer in #g*cm^-3#.

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