# What is the possible identity of a metal that has a 23.9*g mass and a volume of 8.8*mL?

$\text{Density, } \rho$ $=$ $\text{Mass"/"Volume}$ $=$ $\frac{23.9 \cdot g}{8.8 \cdot m L}$ $=$ $2.7 \cdot g \cdot m {L}^{-} 1$. As metals go, this is not particularly dense, and we could tentatively identify the metal as aluminum.