What is the possible identity of a metal that has a #23.9*g# mass and a volume of #8.8*mL#?

1 Answer
Sep 16, 2016

Answer:

Possibly aluminum.

Explanation:

#"Density, "rho# #=# #"Mass"/"Volume"# #=# #(23.9*g)/(8.8*mL)# #=# #2.7*g*mL^-1#. As metals go, this is not particularly dense, and we could tentatively identify the metal as aluminum.