Question

What is the possible identity of a metal that has a `23.9*g` mass and a volume of `8.8*mL`?

Answer 1

Possibly aluminum.

Explanation:

`"Density, "rho` `=` `"Mass"/"Volume"` `=` `(23.9*g)/(8.8*mL)` `=` `2.7*g*mL^-1`. As metals go, this is not particularly dense, and we could tentatively identify the metal as aluminum.