# How do you solve x^2 +8x - 6 = 0 by completing the square?

Sep 18, 2016

$x = - 4 \pm \sqrt{22}$

#### Explanation:

$1 \left({x}^{2} + 8 x + m - m\right) = 6$

The goal here is to find the value of m that will make the expression in parentheses a perfect square.

$1 \left({x}^{2} + 8 x + 16 - 16\right) = 6$

$1 \left({x}^{2} + 8 x + 16\right) - 16 = 6$

$1 {\left(x + 4\right)}^{2} = 22$

$x + 4 = \pm \sqrt{22}$

$x = - 4 \pm \sqrt{22}$

Hopefully this helps!