# Question bfe87

Sep 19, 2016

$\pm 2 \sqrt{3}$

#### Explanation:

You are looking for squared numbers that you can 'remove' from the square root

Known:$\text{ } 3 \times 4 = 12$

But 4 is the same as ${2}^{2}$ so we can write 12 as $3 \times {2}^{2}$ giving:

$\sqrt{3 \times {2}^{2}}$

Take the ${2}^{2}$ outside the square root giving:

2sqrt(3)" "color(brown)( larr" part answer")#

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Observe that in taking the ${2}^{2}$ out of the square root we have to apply $\sqrt{{2}^{2}} = 2$

Actually it is $\pm 2$ as :$\left(- 2\right) \times \left(- 2\right) = \left(+ 2\right) \times \left(+ 2\right) = 4$

So if you wish to be totally correct you would write:

$\sqrt{12} = \pm 2 \sqrt{3}$