# Question b6f66

Sep 27, 2016

$\frac{2}{t}$

#### Explanation:

${s}^{-} 1 \frac{{t}^{-} 1}{s} ^ - 1 + {t}^{-} 1$

Let's simplify first and attend to the negative indices..

$\cancel{{s}^{-} 1} \frac{{t}^{-} 1}{\cancel{{s}^{-} 1}} + {t}^{-} 1$

=${t}^{-} 1 + {t}^{-} 1$

=$\frac{1}{t} + \frac{1}{t}$

As these are like terms they can be added to give $\frac{2}{t}$

HOwever, if we want factors, we can use 1/t) as the common factor:

$\frac{1}{t} + \frac{1}{t} = \frac{1}{t} \left(1 + 1\right)$

But this gives the same outcome..

$\frac{1}{t} \left(2\right) = \frac{2}{t}$