Question #4099b

2 Answers
Oct 6, 2016

Answer:

#132,000#

Explanation:

Let us assume that the population in 1999 is #x#

So #x + 8% "of " x =142,560#

#x+8/100x=142,560#

#108/100x=142,560#

#x=14,2560xx100/108#

#x=132,000#

Oct 6, 2016

Answer:

#132,000# in 1999

Explanation:

This is an example of a reverse percentage where we know the value AFTER an increase has happened, but we do not know what the original amount was.

Do NOT be tempted to just find #8%# of the population in 2000 and subtract!

Here is a different approach from how Annie did it.

Percentages are always in direct proportion.
Let's compare what we know.

Let the population in 1999 be #x#
We can consider that as #100%#

In 2000, the population had increased by #8%#
The population of 142,560 represents #108%#

#x/100 = (142,560)/108#

#x = (142,560xx100)/108#

#x = 132,000#