# Question #17f7b

Oct 7, 2016

$- \infty$

#### Explanation:

${\lim}_{x \to {0}^{+}} \frac{s e n x \ln x}{x}$

The limit of the products in the product of the limits
$= {\lim}_{x \to {0}^{+}} \frac{s e n x}{x} {\lim}_{x \to 0} \ln x$

As we have

$= {\lim}_{x \to {0}^{+}} \frac{s e n x}{x} = 1$ which is one of the fundamental trig limits

And

${\lim}_{x \to {0}^{+}} \ln x = = - \infty$