Question #6fc81

Question

1333 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-05T17:35:54

The new volume is #=4.17L#

#P_1V_1=P_2V_2# at constant temperature

The initial pressure is #P_1=100kPa#

The initial volume is #V_1=9L#

The final pressure is #P_2=216Pa#

The final volume is

#V_2=P_1/P_2*V_1=100/216*9=4.17L#