Question #6fc81

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Answer 1 · 2018-01-05T17:35:54

The new volume is $=4.17L$

$P_1V_1=P_2V_2$ at constant temperature

The initial pressure is $P_1=100kPa$

The initial volume is $V_1=9L$

The final pressure is $P_2=216Pa$

The final volume is

$V_2=P_1/P_2*V_1=100/216*9=4.17L$