# Question #9cda7

##### 1 Answer

Oct 13, 2016

#### Explanation:

We will use the following properties of exponents and of logarithms:

#a^(-x) = 1/a^x# #(a^x)^y = a^(xy)# #a^x*a^y = a^(x+y)# #log_a(a^x) = x#

With those