58.44 grams of NaCl and you dissolved it in exactly 2.00 kg of pure water (the solvent). What would be the molality of the solution?

1 Answer
May 15, 2014

The molality of the solution is 0.500 mol/kg.

The molality of a solution is the number of moles of solute per kilogram of solvent.

Molality = #"moles of solute"/"kilograms of solvent"#

In this case, NaCl is the solute and water is the solvent.

Moles of NaCl = 58.44 g NaCl × #(1" mol NaCl")/(58.44" g NaCl")# = 1.0000 mol NaCl

Kilograms of water = 2.00 kg water

Molality = #"moles of solute"/"kilograms of solvent" × (1.0000" mol")/(2.00" kg")# = 0.500 mol/kg