# 58.44 grams of NaCl and you dissolved it in exactly 2.00 kg of pure water (the solvent). What would be the molality of the solution?

May 15, 2014

The molality of the solution is 0.500 mol/kg.

The molality of a solution is the number of moles of solute per kilogram of solvent.

Molality = $\text{moles of solute"/"kilograms of solvent}$

In this case, NaCl is the solute and water is the solvent.

Moles of NaCl = 58.44 g NaCl × $\left(1 \text{ mol NaCl")/(58.44" g NaCl}\right)$ = 1.0000 mol NaCl

Kilograms of water = 2.00 kg water

Molality = "moles of solute"/"kilograms of solvent" × (1.0000" mol")/(2.00" kg") = 0.500 mol/kg