# What is the molality when 0.75 mol is dissolved in 2.50 L of solvent?

To answer this question we will assume that the solvent is water. The mass of the solvent will be 2.50kg.

NOTE: The density of water is 1g = 1mL

$\frac{2.50 L}{1}$x$\frac{1000 m L}{1 L}$x$\frac{1 g}{1 m L}$x$\frac{1 k g}{1000 g}$= 2.50 kg

To calculate the molality we use the relationship-

$\frac{m o l s o l u t e}{k g s o l v e n t}$ = molality

$\frac{0.75 m o l s o l u t e}{2.50 k g s o l v e n t}$ = 0.30$m$