# How does nitric acid behave in a titration?

Jul 29, 2017

This question is a bit of a $\text{non sequitir}$........

#### Explanation:

Certainly, I could use dilute nitric acid in a titration, and this reacts in the regular way with a strong base.......

$H N {O}_{3} \left(a q\right) + N a O H \left(a q\right) \rightarrow N a N {O}_{3} \left(a q\right) + {H}_{2} O \left(l\right)$

At neutrality, $p H$ would be very close to $7$.

If I am barking up the wrong tree, would you please refine the question?