# Question #00a96

Aug 29, 2017

$N a N {O}_{3} \left(a q\right) + H C l \left(a q\right) \stackrel{{H}_{2} O}{\rightarrow} N {a}^{+} + N {O}_{3}^{-} + {H}^{+} + C {l}^{-}$
You can write the metathesis reactions if you like but there is neither a precipitate nor neutralization. We represent the $\text{protium ion}$ as ${H}^{+}$, and we could equally represent it as the $\text{hydronium ion}$, ${H}_{3} {O}^{+}$. We use these as shorthands to represent the acidium species in solution, which is probably a cluster of 3-4 water molecules, WITH AN EXTRA ${H}^{+}$ ion, i.e. ${H}_{7} {O}_{3}^{+}$ or ${H}_{9} {O}_{4}^{+}$....The extra protons exchanges rapidly, tunnels if you like, between different water clusters.