Question #12df8

1 Answer
Jan 6, 2017

Answer:

I got: #v=6.8m/s#

Explanation:

I would use conservation of momentum #p# applied to the entire system of crane and cart and write:
#p_("before")=p_("after")#
in numbers:
#1200*10.8=(1200+691)v#
where on the right you have tye total mass of cart plus load and #v# will be the speed after the loading.
we get:
#v=(1200*10.8)/(1200+691)=6.8m/s#