Question

Question #12df8

Answer 1

I got: `v=6.8m/s`

Explanation:

I would use conservation of momentum `p` applied to the entire system of crane and cart and write:
`p_("before")=p_("after")`
in numbers:
`1200*10.8=(1200+691)v`
where on the right you have tye total mass of cart plus load and `v` will be the speed after the loading.
we get:
`v=(1200*10.8)/(1200+691)=6.8m/s`