Question

Question #efd42

Answer 1

Given quadratic equation of m is

`2m^2-16m+8=0`

`=>m^2-8m+4=0`

It being a quasratic equation it will have only two values that satisfy the equation. Let these are a and b.

So `(m-a)(m-b)=0` should be the qudratic equation.

Comparing these two equations
we have

`(m-a)(m-b)=m^2-8m+4`

`m^2-(a+b)m+ab=m^2-8m+4`

Comparing LHS and RHS we get

`a+b=8`

~~~~~~~~~~~~~~~~~~~~~~~~~~±~
For any quadratic equation

`ax^2+bx+c=0`,

if `alpha and beta` are two values of x that satisfy the equation then

`alpha+beta=-b/a and alphabeta=c/a`