Solve the equation $-6x^2-24=-18x$ ?

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Answer 1 · 2016-10-31T16:35:10

$x=3/2+-sqrt7/2i$

$-6x^2-24=-18x$

$hArr6x^2-18x+24=0$ and dividing by $6$ , we get

$x^2-3x+4=0$

$x^3-2×3/2×x+(3/2)^2-(3/2)^2+4=0$

or $(x-3/2)^2-9/4+4=0$

or $(x-3/2)^2-(-7/4)=0$

or $(x-3/2)^2-(sqrt7/2i)^2=0$

or $(x-3/2+sqrt7/2i)(x-3/2-sqrt7/2i)=0$

i.e. $x=3/2+-sqrt7/2i$

Solve the equation -6x^2-24=-18x-6x^2-24=-18x?