Solve the equation #-6x^2-24=-18x#?

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Answer 1 · 2016-10-31T16:35:10

#x=3/2+-sqrt7/2i#

#-6x^2-24=-18x#

#hArr6x^2-18x+24=0# and dividing by #6#, we get

#x^2-3x+4=0#

#x^3-2×3/2×x+(3/2)^2-(3/2)^2+4=0#

or #(x-3/2)^2-9/4+4=0#

or #(x-3/2)^2-(-7/4)=0#

or #(x-3/2)^2-(sqrt7/2i)^2=0#

or#(x-3/2+sqrt7/2i)(x-3/2-sqrt7/2i)=0#

i.e. #x=3/2+-sqrt7/2i#