Question #8d0dc

The cosecutive integers are $7 , 8 , 9$.
Let the three consecutive integers be $\left(a - 1\right) , a , \left(a + 1\right)$. By given condition, $3 \left(a - 1\right) = \left(a + 1\right) + 12 \mathmr{and} 3 a - 3 = a + 13 \mathmr{and} 2 a = 16 \mathmr{and} a = 8$.
So integers are $\left(8 - 1\right) , 8 , \left(8 + 1\right) \mathmr{and} 7 , 8 , 9$[Ans]