Question #4eef0

1 Answer
Jan 11, 2017

# 1+sec(sqrt(x)) #

Explanation:

In a define integral where one of the limits is a variable it is poor notation to use the same variable as the variable of integration, so I will write

# int_pi^sqrt(x) \ sec(x)tan(x) \ dx # as # int_pi^sqrt(x) \ sec(t)tan(t) \ dt #

We use the known result

# d/dxsecx = secxtanx #

This gives us (without the need for a substitution):

# int_pi^sqrt(x) \ sec(t)tan(t) \ dt = [sect]_pi^sqrt(x) #
# " " = sec(sqrt(x)) - sec(pi) #
# " " = sec(sqrt(x)) - (-1) #
# " " = 1+sec(sqrt(x)) #