# Question #aa61d

##### 1 Answer
Nov 7, 2016

Because the concentration of charged particles in pure water is vanishingly small.

#### Explanation:

We know that water does undergo autoprotolysis:

$2 {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s {H}_{3} {O}^{+} + H {O}^{-}$ ${K}_{a} = {10}^{-} 14$

At standard (and higher) temperatures, the ${K}_{a}$ value is quite small. The result is that water is a poor conductor because of the absence of species that can carry a charge.