# A "1.32 L" volume of gas has a pressure of "1.00 atm". What will the volume be if the pressure is increased to "30.0 atm"?

Nov 8, 2016

The final volume will be $\text{0.0440 L}$

#### Explanation:

This question involves Boyle's law, which states that the volume of a given amount of gas varies inversely to its pressure as long as the temperature and mass remain constant.

${P}_{1} = \text{1.00 atm}$
${V}_{1} = \text{1.32 L}$
${P}_{2} = \text{30.0 atm}$
${V}_{2} = \text{???}$

Solution
Rearrange the equation to isolate ${V}_{2}$. Substitute the known values into the equation and solve.

${V}_{2} = \frac{{P}_{1} {V}_{1}}{P} _ 2$

V_2=(1.00cancel"atm"xx1.32"L")/(30.0cancel"atm")="0.0440 L"