Question

Question #64165

Answer 1

`6.36 L`

Explanation:

* I am going to assume that you mean a 11.0 L sample of `Cl_2` gas

To find the final volume of chlorine gas we can use Boyle's Law:

Based on the information you've given me, we know the following variables:

`P_1` = 26.0 atm
`V_1` = 11.0 L
`P_2` = 45.0 atm
`V_2` = `x`

Since we don't know what `V_2` is, the equation has to be rearranged by dividing both sides by `P_2` to get `V_2` by itself:

`V_2 = (P_1xxV_1)/P_2`

Now, just plug the given values into the equation:

`V_2 = (26.0 cancel"atm" xx11.0L)/(45.0cancel"atm")`

`V_2` = 6.36 L