Question #64165

1 Answer
Dec 19, 2016

Answer:

#6.36 L#

Explanation:

* I am going to assume that you mean a 11.0 L sample of #Cl_2# gas

To find the final volume of chlorine gas we can use Boyle's Law:
http://slideplayer.com/slide/5281881/

Based on the information you've given me, we know the following variables:

#P_1# = 26.0 atm
#V_1# = 11.0 L
#P_2# = 45.0 atm
#V_2# = #x#

Since we don't know what #V_2# is, the equation has to be rearranged by dividing both sides by #P_2# to get #V_2# by itself:

#V_2 = (P_1xxV_1)/P_2#

Now, just plug the given values into the equation:

#V_2 = (26.0 cancel"atm" xx11.0L)/(45.0cancel"atm")#

#V_2# = 6.36 L