# What does chloride ion do in aqueous solution?

Jun 23, 2017

What does the $C {l}^{-}$ do...........?

#### Explanation:

Well it is solvated by several water molecules. And as the conjugate base of a strong acid it delivers electrical neutrality to the solution.

This is taken from an older answer.......

$H C l \left(g\right)$ is a source of hydronium ion, ${H}_{3} {O}^{+}$ in aqueous solution.........

We may take a tank of $H C l \left(g\right)$, and we can bleed it in to water to give an AQUEOUS solution that we could represent as $H C l \left(a q\right)$ OR ${H}_{3} {O}^{+}$ and Cl^−.

$H C l \left(g\right) \stackrel{{H}_{2} O}{\rightarrow} {\underbrace{{H}_{3} {O}^{+}}}_{\text{hydronium ion}} + C {l}^{-}$

In each case this is a REPRESENTATION of what occurs in solution. If we bleed in enuff gas, we achieve saturation at a concentration of approx. $10.6 \cdot m o l \cdot {L}^{-} 1$ with respect to hydrochloric acid. Sometimes when you use conc. hydrochloric acid in a lab (and of course you are wearing spectacles to protect your mincers, and a lab coat to protect your clothes), you inadvertently get a whiff of the $H C l$ vapour, and you know it!

As far as anyone knows, the actual acidium ion in solution is
${H}_{5} {O}_{2}^{+}$ or ${H}_{7} {O}_{3}^{+}$, i.e. a cluster of 2 or 3 or 4 water molecules with an EXTRA ${H}^{+}$ tacked on. We represent it in solution (without loss of generality) as ${H}_{3} {O}^{+}$, the $\text{hydronium ion}$, which is clearly the conjugate acid of ${H}_{2} O$.

Note that the ${H}^{+}$ is quite mobile, and passes, tunnels if you like, the extra ${H}^{+}$ from cluster to cluster. If you have ever played rugby, I have always liked to compare to this to when the forwards form a maul, and can pass it from hand to hand to the back of the maul while the maul is still formed. Of course, tunnelling, proton transfer, is more likely in a cluster of water molecules, so the analogy might not be particularly apt in that there is definite transfer of a ball in a maul, but a charge in a water cluster. For this reason both ${H}^{+}$ and $H {O}^{-}$ have substantial mobility in aqueous solution.

${H}^{+} + {e}^{-} \rightarrow \frac{1}{2} {H}_{2} \left(g\right)$

With an electron source, a metal, the metal may be oxidized......

Depending at which level you are at (and I don't know!, which is part of the problem in answering questions on this site), you might not have to know the details at this level of sophistication. The level I have addressed here is probably 1st/2nd year undergrad.........