# How does the electronic and geometric structure differ between the ozone and water molecules?

What is the bond angle around the central atom for $s {p}^{3}$ hybridization versus $s {p}^{2}$ hybridization.
We use valence bond formalism and $s {p}^{3}$ hybridization for the water molecule, and $s {p}^{2}$ hybridization for ozone.
To a first approximation, $\angle H - O - H$ is ${109.5}^{\circ}$, and $\angle O - O - O$ is ${120.0}^{\circ}$. Of course, the oxygen lone pair electrons compress this angle (substantially), however tetrahedral versus trigonal planar geometry with respect to both bonding electron pairs and non-bonding pairs, clearly dictates that $\angle H - O - H$ should be more compressed.