Question #fc138

1 Answer

k^3+3k^2-25k-75=(k+3)(k-5)(k+5)

Explanation:

Factor by grouping first

k^3+3k^2-25k-75=k^2(k+3)-25(k+3)

factor out the common binomial factor (k+3)

k^2(k+3)-25(k+3)=(k+3)(k^2-25)

then factor the
difference of two squares k^2-25=(k-5)(k+5)

then continue

(k+3)(k^2-25)=(k+3)(k-5)(k+5)

the complete factored form is

k^3+3k^2-25k-75=(k+3)(k-5)(k+5)

God bless....I hope the explanation is useful.