# Question #35177

Dec 5, 2016

The decreasing order of bond polarity is:
$B - F > B - O > B - N > B - C$.

#### Explanation:

There is something common in all the following bonds given. Boron $\left(B\right)$ atom is common in all of the bonds.

So, among $N , O , F , C$ atoms, $F$ atom has the highest electro negativity. So, fluorine has the highest capability of attracting the bonded pair of electrons towards itself, thus making the $B - F$ bond most polar.

Now, among the rest, oxygen $\left(O\right)$ atom ranks second in magnitude of electro negativity. Then ranks nitrogen atom $\left(N\right)$ and lastly carbon $\left(C\right)$ atom.

So, the order of decreasing bond polarity is:

$B - F > B - O > B - N > B - C$.

Hope it Helps :)