Question #35177

1 Answer
Dec 5, 2016

Answer:

The decreasing order of bond polarity is:
#B-F>B-O>B-N>B-C#.

Explanation:

There is something common in all the following bonds given. Boron #(B)# atom is common in all of the bonds.

So, among #N, O, F, C# atoms, #F# atom has the highest electro negativity. So, fluorine has the highest capability of attracting the bonded pair of electrons towards itself, thus making the #B-F# bond most polar.

Now, among the rest, oxygen #(O)# atom ranks second in magnitude of electro negativity. Then ranks nitrogen atom #(N)# and lastly carbon #(C)# atom.

So, the order of decreasing bond polarity is:

#B-F>B-O>B-N>B-C#.

Hope it Helps :)