Question #35177

1 Answer
Dec 5, 2016

The decreasing order of bond polarity is:
B-F>B-O>B-N>B-C.

Explanation:

There is something common in all the following bonds given. Boron (B) atom is common in all of the bonds.

So, among N, O, F, C atoms, F atom has the highest electro negativity. So, fluorine has the highest capability of attracting the bonded pair of electrons towards itself, thus making the B-F bond most polar.

Now, among the rest, oxygen (O) atom ranks second in magnitude of electro negativity. Then ranks nitrogen atom (N) and lastly carbon (C) atom.

So, the order of decreasing bond polarity is:

B-F>B-O>B-N>B-C.

Hope it Helps :)