How do we describe the #"electronic geometry"# with respect to #SBr_2#? #(a)# #"bent"#; #(b)# #"trigonal planar"#; #(c)# #"tetrahedral"#; #(d)# #"octahedral"#?

2 Answers
Dec 9, 2016

Answer:

C

Explanation:

There are two bonded species and two lone pair about the central atom #S#. Therefore the bonded species to lone pair ratio is 2:2.

There are four electron cloud about the central about #S#.
The electronic geometry is tetrahedral .

Again, the bonded species to lone pair ratio is 2:2. The molecular geometry is bent. (as you can see from the image you have provided)

Because of the two lone pair about the central atom #S#, the bond angles will be slightly less than #109.5°#.

The answer to the question in the image that you have provided is choice c.

Dec 9, 2016

Answer:

#"Option c"#

Explanation:

The electron pair geometry, bonding and non-bonding, is TETRAHEDRAL to a first approximation. If you don't grasp why, holler.

However, we describe molecular geometry on the basis of bonding pairs not lone pairs. The lone pairs would compress the #/_Br-S-Br# from #109.5# to approx. #105^@# because of the repulsive influence of the 2 lone pairs.