# How to factor x^2+7x+6?

$\left(x + 6\right) \left(x + 1\right)$

#### Explanation:

For this question, we want to find factors, $a , b$ where:

$a \times b = 6$ and $a + b = 7$

In this case, we can set $a = 6 , b = 1$, which gives us:

$\left(x + 6\right) \left(x + 1\right)$

We can show that this works by multiplying it out:

$x \times x = {x}^{2}$
$x \times 1 = x$
$6 \times x = 6 x$
$6 \times 1 = 6$

and now add them all together:

${x}^{2} + x + 6 x + 6 = {x}^{2} + 7 x + 6$