# How do you write 16x^2 – 48x + 36 as a perfect square trinomial?

Oct 29, 2014

Since

$\left\{\begin{matrix}\sqrt{16 {x}^{2}} = 4 x \\ - 48 \text{ is negative} \\ \sqrt{36} = 6\end{matrix}\right.$,

we have

$16 {x}^{2} - 48 x + 36 = {\left(4 x - 6\right)}^{2}$

I hope that this was helpful.