# How do you factor 16x^2-36 using the difference of squares?

$16 {x}^{2} - 36$ is the difference of two squares and will always factor in the following pattern: ${x}^{2} - {y}^{2} = \left(x + y\right) \left(x - y\right)$
The perfect square of $16 {x}^{2}$ is $4 x$
$16 {x}^{2} - 36$ = (4x + 6)(4x - 6)