Question

Question #c4621

Answer 1

There are 2 real solutions: x ≈ ± 2.63571322227139...

Explanation:

The equations cannot be solved by algebraic methods. You can solve the equations:

`-2sin(x) - ln(-x) = 0; -oo < x < 0`

`2sin(x) - ln(x) = 0; 0 < x < oo`

Using a numerical analysis method, for example Newton's Method and a computation tool like Excel or MatLab.

I used WolframAlpha to obtain the two values:

x ≈ ± 2.63571322227139...