# Question 98f7b

Dec 12, 2016

${x}^{2} + \left(\frac{9}{16}\right) {x}^{2}$ transforms into $\left(\frac{25}{16}\right) {x}^{2}$ as shown below.

#### Explanation:

To factor this expression gives:

$\left(1 + \frac{9}{16}\right) {x}^{2}$

To add 1 and $\frac{9}{16}$ we must get this over a common denominator of $16$:

16/16*1 + 9/16)x^2 ->#

$\left(\frac{16}{16} + \frac{9}{16}\right) {x}^{2} \to$

$\left(\frac{25}{16}\right) {x}^{2}$