Question #b5be7

1 Answer
Dec 19, 2016

Answer:

The specific heat capacity of the metal is #"0.11 cal·°C"^"-1""g"^"-1"#.

Explanation:

The formula for the heat #q# absorbed by a substance is

#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#

where

#m# is the mass of the substance

#c# is the specific heat capacity of the material

#ΔT# is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

#c = q/(mΔT)#

In this problem,

#q = "26.5 cal"#
#m = "50 g"#
#ΔT = "5 °C"#

#c = "26.5 cal"/"50 g × 5 °C" = "0.11 cal·°C"^"-1""g"^"-1"#