# Question b5be7

Dec 19, 2016

The specific heat capacity of the metal is $\text{0.11 cal·°C"^"-1""g"^"-1}$.

#### Explanation:

The formula for the heat $q$ absorbed by a substance is

color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "

where

$m$ is the mass of the substance

$c$ is the specific heat capacity of the material

ΔT is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

c = q/(mΔT)

In this problem,

$q = \text{26.5 cal}$
$m = \text{50 g}$
ΔT = "5 °C"#

$c = \text{26.5 cal"/"50 g × 5 °C" = "0.11 cal·°C"^"-1""g"^"-1}$