A beaker whose mass was #345.8*g# was filled with a #225*mL# volume of carbon tetrachloride, to give a combined mass of #703.55*g#. Given these data, what is #rho_"carbon tetrachloride"#?

1 Answer
Dec 17, 2016

Answer:

#rho_"carbon tetrachloride"="Mass of carbon tetrachloride"/"Volume of carbon tetrachloride"#

Explanation:

And so we put the given numbers in:

#rho_"carbon tetrachloride"=(703.55*g-345.8*g)/(225*mL)=??g*mL^-1#

Because #1*g*mL^-1=1xx10^-3kg*(10^-3L)^-1=1xx10^-3kgxx10^3*L^-1=kg*L^-1#, the #"density"# has the same figures in #kg*L^-1#.

#"Carbon tetrachloride"# will form an immiscible layer with water. Will it float? How can you tell from these figures?