Question

Question #ad049

Answer 1

Ammonia gas behaves as an alkali in water........................

Explanation:

Ammonia gas is exceptionally soluble in water, and an experiment called the `"ammonia fountain"` (which you'll have to seek out on the interwebz) spectacularly demonstrates this. In aqueous solution, ammonia behaves as a weak base, and the given equilibrium lies somewhat to the right:

`NH_3(aq) + H_2O(aq) rightleftharpoons NH_4^+ + HO^-` `;K_"eq"=10^(-4.75)`

If you are in first year university, can you tell me the `pH` of a `1*mol*L^-1` solution of `NH_3(aq)`?

`K_"eq"=10^(-4.75)=([NH_4^+][HO^-])/([NH_3(aq)])`