# Question #39436

Jan 1, 2017

$9 \text{ and } 15$

#### Explanation:

Let one number be represented by x

Then the other number will be $2 x - 3$ That is 3 less than twice the other which is x.

Forming an equation.

$\Rightarrow x + 2 x - 3 = 24 \leftarrow \text{ sum of numbers is 24}$

$\Rightarrow 3 x - 3 = 24$

add 3 to both sides of the equation.

$3 x \cancel{- 3} \cancel{+ 3} = 24 + 3$

$\Rightarrow 3 x = 27$

To solve for x, divide both sides by 3

$\frac{\cancel{3} x}{\cancel{3}} = \frac{27}{3}$

$\Rightarrow x = 9$

The 2 numbers are.

$x = 9 \text{ and } 2 x - 3 = \left(2 \times 9\right) - 3 = 18 - 3 = 15$

$\textcolor{b l u e}{\text{As a check }} 9 + 15 = 24$