# Question #0310e

Jan 5, 2017

See the full process for factoring this expression below

#### Explanation:

We can rewrite this expression as:

$\frac{5 {x}^{3} + 15 {x}^{2} + 20 x}{5 x}$

We can first factor $\textcolor{red}{5 x}$ from the numerator.

$\frac{\left(\textcolor{red}{5 x} \times {x}^{2}\right) + \left(\textcolor{red}{5 x} \times 3 x\right) + \left(\textcolor{red}{5 x} \times 4\right)}{5 x}$

$\frac{\textcolor{red}{5 x} \left({x}^{2} + 3 x + 4\right)}{5 x}$

We can now eliminate the $5 x$ terms through cancellation.

$\frac{\cancel{\textcolor{red}{5 x}} \left({x}^{2} + 3 x + 4\right)}{\textcolor{red}{\cancel{\textcolor{b l a c k}{5 x}}}}$

${x}^{2} + 3 x + 4$