Question #0310e

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Answer 1 · 2017-01-05T14:25:35

See the full process for factoring this expression below

We can rewrite this expression as:

$(5x^3 + 15x^2 + 20x)/(5x)$

We can first factor $color(red)(5x)$ from the numerator.

$((color(red)(5x) xx x^2) + (color(red)(5x) xx 3x) + (color(red)(5x) xx 4))/(5x)$

$(color(red)(5x)(x^2 + 3x + 4))/(5x)$

We can now eliminate the $5x$ terms through cancellation.

$(cancel(color(red)(5x))(x^2 + 3x + 4))/color(red)(cancel(color(black)(5x)))$

$x^2 + 3x + 4$