# How do you factor 12c^2-75 completely?

Oct 28, 2014

$12 {c}^{2} - 75$

by factoring out 3,

$= 3 \left(4 {c}^{2} - 25\right)$

by ${a}^{2} - {b}^{2} = \left(a + b\right) \left(a - b\right)$,

$= 3 \left(2 c + 5\right) \left(2 c - 5\right)$

I hope that this was helpful.