# Express (1-sin^2x)/cosx in terms of sine ratio of x and / or its multiples?

Jan 3, 2017

#### Explanation:

$\frac{1 - {\sin}^{2} x}{\cos x}$

= ${\cos}^{2} \frac{x}{\cos} x$

= $\cos x$

= $\frac{2 \sin x \cos x}{2 \sin x}$

= $\frac{\sin 2 x}{2 \sin x}$