Question

Question #8f739

Answer 1

Area swept by minute hand: `(7pi)/4` sq.cm.

Explanation:

I have assumed underoot 21 means `sqrt(21)`

The surface area of the clock when the minute hand makes 1 full rotation is
`"Area"_circle = pir^2 =pi(sqrt(21))^2=21pi`

During the interval from 7:00 to 7:05, the minute hand sweeps `1/12` of its full surface area.

`"Area"_"swept 7:00 to 7:05"=1/12xx21pi = (7pi)/4`